I have a Question concerning the Calculation from Chemstation.
We have a run of a trace analysis of a solvent.
Our calibration table got 2 components.
Solvent 1 amount 79. mg/L Area 210
Solvent 2 amount 1.0 mg/L Area 397 ISTD
Std Run Run1 Run2
Solvent 1 amount 79.0 mg/L Area 213 amount area 3,7 e-1 amt Area Ratio 146.2 Area 210 amt area 3,75 e-1 amt Area Ratio 149.2
Solvent 2 amount 1.0 mg/L Area 394 amount area 2,5 e-3 amt Area Ratio 1.0 Area 397 amt area 2,51 e-3 amt Area Ratio 1.0
Solvent 1 amount 31,85 mg/L Area 149
Solvent 2 amount 1.0 mg/L Area 398
So the result is 31,85 mg/L ( The Results are from the Chemstation )
We want to reproduce the result on the Open Labs 2.1
Solvent 1 amount 79,0 mg/L Area 290,7
Solvent 2 amount 1.0 mg/L Area 532,421
Calculation of the calculation factor is Area Solvent 2 divide Area Solvent 1. Which is here 1,8 and above 1.9 so the relativity is the same
So we take this factor multiply it by 50 then 2 then 0.79.
This value we take to calculate its around 145 = F
The calculation after is Solven1 amount =( ( area solvent 1/ area solvent 2 ) * F * 50 * 2 ) / 10000
No matter what I do I just don't get the 32 mg.. I assume that there is some Factor that the Chemstation calculates the result with.
So the 2 main questions are.
Is there a chance to review the calculation from the chemstation which is bound in the method ?
2nd how the Chemstation calculate the Value of 32 mg/L ?
If you need more Details let me know.