Hello,

I have a Question concerning the Calculation from Chemstation.

We have a run of a trace analysis of a solvent.

Our calibration table got 2 components.

Solvent 1 amount 79. mg/L Area 210

Solvent 2 amount 1.0 mg/L Area 397 ISTD

Std Run Run1 Run2

Solvent 1 amount 79.0 mg/L Area 213 amount area 3,7 e-1 amt Area Ratio 146.2 Area 210 amt area 3,75 e-1 amt Area Ratio 149.2

Solvent 2 amount 1.0 mg/L Area 394 amount area 2,5 e-3 amt Area Ratio 1.0 Area 397 amt area 2,51 e-3 amt Area Ratio 1.0

SST Run

**Solvent 1 amount 31,85 mg/L Area 149 **

Solvent 2 amount 1.0 mg/L Area 398

So the result is 31,85 mg/L ( The Results are from the Chemstation )

We want to reproduce the result on the Open Labs 2.1

Solvent 1 amount 79,0 mg/L Area 290,7

Solvent 2 amount 1.0 mg/L Area 532,421

Calculation of the calculation factor is Area Solvent 2 divide Area Solvent 1. Which is here 1,8 and above 1.9 so the relativity is the same

So we take this factor multiply it by 50 then 2 then 0.79.

This value we take to calculate its around 145 = F

The calculation after is Solven1 amount =( ( area solvent 1/ area solvent 2 ) * F * 50 * 2 ) / 10000

No matter what I do I just don't get the 32 mg.. I assume that there is some Factor that the Chemstation calculates the result with.

So the 2 main questions are.

Is there a chance to review the calculation from the chemstation which is bound in the method ?

2nd how the Chemstation calculate the Value of 32 mg/L ?

If you need more Details let me know.